A heat engine operating between 100 degree celcius and 700 degree celcius has an efficiency equal to 40% of the maximum theoretical efficiency. How much energy does this engine extract from the hot reservoir in order to do 5000 J oe mechanical work?

Emax(carnot engine)=1-(Tc/Th)=1-(373/973)~0. 617

Actual efficiency is 30%of max efficiency so 30%(0. 617)~0. 185 which means. 18. 5 % effiecient u take that and plug it in the normal effieciency formula for engine which is (Qh-Qc)/Qh we have been given the value of work output which in other words mean Qh-Qc= 5000 plug that and find the value for Qh , Qh=5000/0. 185~ 27027. 8J

A heat engine operating b/n 100°c and 700°c has efficiency equal to 40% the maximum theoretical efficiency.how muh does this extract from the hot reservoir in order to do 500J of mechanical work?

1005

The actual efficiency is 40% of

maximum theoretical efficiency w/c is [1-(373K/973K)]=0.62. Actual efficiency =0.62*40% => 24.8% now we can find the heat of the reservoir!
0.248=5000J/Qh
Qh =5000J/0.248
QH =20161.3J
The energy required to extracted from the hot reservoir is equal to QC!
QH=QC+W
QC=QH-W
QC=20161.3-5000J
QC=15161.3J.
So the answer will be 15161.3J!

So 40 percent of Energy equals 5000?

Energy= 5000/.4

202.6

My bad make it 40% and the answer becomes 20270. 8J

Natural

Heat engine

Qc-QH=by what formula