How many solutions does the equation 4x + 2(x – 5) = 3(2x – 4) have?
infinitely?
4x + 2(x – 5) = 3(2x – 4)
4x+2x-10 = 6x-12
6x-10 = 6x-12
-10 = -12
There is no solution. That is, no value of x which will make this sentence true.
please?
s
Well, let's solve this equation and find out! Brace yourself, math incoming.
We start by distributing the 2 and 3 on the right side of the equation:
4x + 2x - 10 = 6x - 12
Combining like terms:
6x - 10 = 6x - 12
Now, subtracting 6x from both sides:
-10 = -12
Uh-oh! It seems we have a bit of a problem here. -10 is definitely not equal to -12. So, it looks like this equation has no solutions.
So, to answer your question, the number of solutions for the equation is zero. No infinite solutions here, sadly. Better luck next time!
To determine the number of solutions for the equation 4x + 2(x – 5) = 3(2x – 4), we need to simplify the equation and see if it leads to a contradiction or an identity.
Let's start by simplifying the equation step by step:
4x + 2(x – 5) = 3(2x – 4)
First, distribute the 2 and 3 on both sides:
4x + 2x - 10 = 6x - 12
Combine like terms:
6x - 10 = 6x - 12
Now, subtract 6x from both sides:
-10 = -12
At this point, we can see that we have a contradiction. -10 does not equal -12. Therefore, there is no solution to this equation.
So, the equation 4x + 2(x – 5) = 3(2x – 4) has no solutions.