Jay draws a square with a side of 4 inches. Ray draws a square with side length of 6 inches. What is the _difference________ in the_area__ of the square?
6 x6=32
4 x 4=16
32-16 = 20 sqin. is this right
ay draws a square with a side of 4 inches. Ray draws a square with side length of 6 inches. What is the _difference________ in the_area__ of the square?
6 x6=32
4 x 4=16
32-16 = 20 sqin. is this right
you would be right, except 6x6 is not 32.
Amazingly, though, 20 is the correct result!
To find the difference in the area between the two squares, you need to calculate the area of each square and then subtract the smaller area from the larger area.
For Jay's square with a side length of 4 inches, you correctly calculated the area as 16 square inches (4 x 4 = 16).
For Ray's square with a side length of 6 inches, the correct calculation for the area would be 36 square inches (6 x 6 = 36).
To find the difference in the area, subtract the smaller area (16 square inches) from the larger area (36 square inches):
36 - 16 = 20 square inches
So, the difference in the area of the squares is 20 square inches. Your calculation is correct!