Ca(ClO3)2 + KCl --> CaCl2 + 3O2 + KCl
Mass of test tube = 7.918g
Mass of KCl/Ca(ClO3)2 mixture + tube = 19.164g
Mass of KCl/CaCl2 residue + tube = 18.635g
What is the weight % of Ca from the Ca(ClO3)2 impurity in the original mixture?
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I keep getting an answer of 5.89% and 69.9% but im not sure if that's correct
To find the weight percentage of Ca from the Ca(ClO3)2 impurity in the original mixture, we need to determine the amount of Ca(ClO3)2 that reacted and the amount of CaCl2 produced.
1. Calculate the mass of the KCl/Ca(ClO3)2 mixture:
Mass of KCl/Ca(ClO3)2 mixture + tube = 19.164g
Mass of test tube = 7.918g
Mass of KCl/Ca(ClO3)2 mixture = 19.164g - 7.918g = 11.246g
2. Calculate the mass of the KCl/CaCl2 residue:
Mass of KCl/CaCl2 residue + tube = 18.635g
Mass of test tube = 7.918g
Mass of KCl/CaCl2 residue = 18.635g - 7.918g = 10.717g
3. Calculate the mass of Ca(ClO3)2 that reacted:
Mass of Ca(ClO3)2 reacted = Mass of KCl/Ca(ClO3)2 mixture - Mass of KCl/CaCl2 residue
Mass of Ca(ClO3)2 reacted = 11.246g - 10.717g = 0.529g
4. Calculate the mass of Ca in the Ca(ClO3)2 impurity:
The molar mass of Ca(ClO3)2 is about 164.08 g/mol.
Moles of Ca(ClO3)2 impurity = Mass of Ca(ClO3)2 reacted / Molar mass of Ca(ClO3)2
Moles of Ca(ClO3)2 impurity = 0.529g / 164.08 g/mol ≈ 0.0032 mol
The molar mass of Ca is about 40.08 g/mol.
Mass of Ca = Moles of Ca(ClO3)2 impurity * Molar mass of Ca
Mass of Ca = 0.0032 mol * 40.08 g/mol ≈ 0.128g
5. Calculate the weight percentage of Ca from the Ca(ClO3)2 impurity:
Weight % of Ca = (Mass of Ca / Mass of KCl/Ca(ClO3)2 mixture) * 100
Weight % of Ca = (0.128g / 11.246g) * 100 ≈ 1.14%
Therefore, the weight percentage of Ca from the Ca(ClO3)2 impurity in the original mixture is approximately 1.14%.