Let A and B be two events in a sample space S such that P(A) = .6 and p(B l A) =.5. Find P (A∩B).
Well, I know that that should start off by finding P(A l B)
which is found using the formula P(A∩B)/ P(B) but I am not given P(B) here so I don't know what to do.
Or wait.. I might be getting the formulas mixed up. I think I must multiply P(A) by P(B l A) right?
For P(A∩B)?
0.3 that is my final answer.
To find P(A∩B), you can use the formula:
P(A∩B) = P(A) * P(B | A)
Given that P(A) = 0.6 and P(B | A) = 0.5, we can substitute these values into the formula:
P(A∩B) = 0.6 * 0.5
P(A∩B) = 0.3
Therefore, the probability of the intersection of events A and B, P(A∩B), is 0.3.