A heat transfer of 9.0×10^5 j is required to convert a block of ice at 20°C.what was the mass of the block of ice

I need assistance please

To determine the mass of the block of ice, we need to use the specific heat capacity equation:

Q = m * c * ΔT

Where:
Q = heat transfer (9.0×10^5 J)
m = mass of the block of ice (unknown)
c = specific heat capacity of ice (approximately 2.09 J/g°C)
ΔT = change in temperature (final temperature - initial temperature)

The final temperature of the ice will be 0°C, while the initial temperature is 20°C. Therefore, the change in temperature (ΔT) will be:

ΔT = 0°C - 20°C = -20°C

Now we can rearrange the equation to solve for the mass (m):

m = Q / (c * ΔT)

Substituting the given values:

m = 9.0×10^5 J / (2.09 J/g°C * -20°C)

Note: The negative sign is included to indicate a decrease in temperature.
Now let's calculate the mass of the block of ice.

To determine the mass of the block of ice, we need to use the specific heat capacity of ice and the amount of heat transferred.

The specific heat capacity of ice is the amount of heat required to raise the temperature of one kilogram of ice by one degree Celsius. It is given as 2.09 J/g°C.

Given:
Heat transfer (Q) = 9.0 × 10^5 J
Temperature change (ΔT) = 20°C

To calculate the mass (m), we can use the formula:
Q = m × c × ΔT

Where:
Q = heat transfer
m = mass
c = specific heat capacity
ΔT = temperature change

Rearranging the formula to solve for mass (m), we get:
m = Q / (c × ΔT)

Substituting the given values, we have:
m = (9.0 × 10^5 J) / (2.09 J/g°C × 20°C)

Calculating this expression, we find:
m ≈ 21475 grams

Therefore, the mass of the block of ice is approximately 21475 grams.