a ball thrown veticallyupwards from ground level hits the ground level hits the ground after 4s. calculate the maximum height it reached during its journey.
max height = t/2 =2s, gravity acc = 9.8m/s^2
x = 1/2at^2 + Vot (Vo will be 0)
x = 1/2 (9.8) (2)^2
x = 19.6 m