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Calculate the theoretical yield of ethyl acetate formed if 10 mL of ethyl alcohol (density = 0.79 ... (density = 0.79 G/mL; MW = 46.1 G/mol ) And 12 ML Of 17.4 M Acetic Acid Were Used .

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  1. g C2H5OH = volume x density = 10 mL x 0.79g/mL = 7.9 g.
    mols C2H5OH = g/molar mass = 7.9/46.1 = approx 0.17(estimate)
    g CH3COOH = volume x density = 012 mL x 17.4 M = approx 210 g (estimate)
    mols CH3COOH = 209/60 = approx 3.5 (estimated)
    You must go through and recalculate ALL estimates (those above AND below)
    This is a limiting reagent (LR) problem.
    ........CH3COOH + C2H5OH ==> CH3COOC2H5 + H2O
    I.........3.5.................0.17...................0........................0
    So C2H5OH is the LR and 0.17 mols ethyl acetate will be formed.
    Theoretical yield is 0.17 mol x molar mass ethyl acetate = ? Check all my work. Post your work if you get stuck.

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    DrBob222

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