Ann is driving down a street at 55 km/h. Suddenly a child runs into the street. If it takes Ann 0.75 s to react and apply the brakes, how many meters will she have moved before she begins to slow down?
(55000 m / 3600 s) * .75 s
Vo = 55km/h = 55,000m/3600s = 15.3 m/s.
d = Vo*T = 15.3*0.75 =
To calculate the distance Ann will have moved before she begins to slow down, we need to find the distance she travels during her reaction time.
Given:
Initial speed of Ann, u = 55 km/h
Time taken for reaction, t = 0.75 s
First, we need to convert the speed from km/h to m/s since we will be working in SI units.
To convert km/h to m/s, we divide the speed by 3.6
55 km/h / 3.6 = 15.28 m/s (rounded to 2 decimal places)
Now, we can calculate the distance traveled during the reaction time using the formula:
Distance = Speed × Time
Distance = 15.28 m/s × 0.75 s
Distance = 11.46 meters (rounded to 2 decimal places)
Therefore, Ann will have moved approximately 11.46 meters before she begins to slow down.
To determine how many meters Ann will have moved before she begins to slow down, we need to calculate the distance she travels during the reaction time.
First, let's convert Ann's speed from km/h to m/s because time is usually measured in seconds and distance in meters.
To convert km/h to m/s, we need to divide Ann's speed by 3.6 (since there are 3.6 seconds in an hour):
55 km/h / 3.6 = 15.28 m/s
Now, let's calculate the distance Ann travels during her reaction time. We can use the formula: distance = speed × time.
Given:
Speed (initial velocity), v = 15.28 m/s
Time, t = 0.75 s
distance = v × t
distance = 15.28 m/s × 0.75 s
distance ≈ 11.46 meters.
Therefore, Ann will have moved approximately 11.46 meters before she begins to slow down.