the compound al2o3 contains 53% metal ,what is the relative atomic mass of aluminium
53% Al so 47% O
Take 100 g sample gives
53 g Al
47 g O.
Convert to mols. x = atomic mass Al.
53/x = ?
47/16 = 2.94
For the formula to be Al2O3, ? must be 2.94*(2/3) = 1.96
Then (53/x) = 1.94 so x = 27
The explanation is not clear
i like the explanation
Please explain how you got the 16
It's ok I understand thanks 😊☺
To find the relative atomic mass of aluminum in the compound Al2O3, we'll need the percent composition of aluminum in Al2O3.
Given that the compound Al2O3 contains 53% metal, we can assume this refers to the aluminum content. Therefore, the percent composition of aluminum in Al2O3 is 53%.
The relative atomic mass (also known as the atomic weight) is the weighted average of the atomic masses of all the isotopes of an element. Since aluminum has multiple isotopes, we need to consider their relative abundance.
The relative atomic mass of aluminum can be calculated using the following formula:
Relative Atomic Mass (Al) = (% Aluminum / 100) * Atomic Mass (Al)
Now, let's substitute the values into the formula:
Relative Atomic Mass (Al) = (53 / 100) * Atomic Mass (Al)
To find the atomic mass of aluminum, we can refer to the periodic table. The atomic mass of aluminum (Al) is approximately 26.98 grams/mole.
Relative Atomic Mass (Al) = (53 / 100) * 26.98
Calculating this:
Relative Atomic Mass (Al) ≈ 0.53 * 26.98
Relative Atomic Mass (Al) ≈ 14.26
Therefore, the relative atomic mass (or atomic weight) of aluminum in Al2O3 is approximately 14.26.