The 1st term of linear sequence is 3 and the 8th term is 31. Find the common difference
a = 3
term(8) = a + 7d
3 + 7d = 31
solve for d
The first terms of a linear sequence is 3 and the 8 terms is 3.find the common difference
I need the answer
I don't understand
To find the common difference in a linear sequence, we can use the formula:
nth term = first term + (n - 1) * common difference
In this case, the first term is given as 3 and the 8th term is given as 31. Let's use these values to solve for the common difference.
For the 8th term:
31 = 3 + (8 - 1) * common difference
Now, simplify the equation:
31 = 3 + 7 * common difference
Next, subtract 3 from both sides:
31 - 3 = 7 * common difference
28 = 7 * common difference
To solve for common difference, divide both sides of the equation by 7:
common difference = 28 / 7 = 4
Therefore, the common difference in this linear sequence is 4.