At what velocity most a conductor of 75mm cut a magnetic field of flux density 0.6Tesla if an ele trim it I've force of 9 volt is to be induced in it. assuming the conductor , field and directional motion are mutually perpendicular
Surely "ele trim it I've" means "electromotive"
Don't you have a handy formula which relates these quantities?
12
To calculate the required velocity of the conductor, we can use Faraday's Law of electromagnetic induction, which states that the induced electromotive force (EMF) is equal to the rate of change of magnetic flux.
The formula is given as:
EMF = B * L * v
Where:
EMF = Electromotive Force (in volts)
B = Magnetic Field (in Tesla)
L = Length of the conductor (in meters)
v = Velocity of the conductor (in meters per second)
In this case, we have:
EMF = 9 volts (as stated in the question)
B = 0.6 Tesla (flux density)
L = 75 mm = 0.075 meters (conductor length)
To find the velocity (v), we rearrange the formula:
v = EMF / (B * L)
Substituting the given values:
v = 9 / (0.6 * 0.075)
= 200 meters per second
Therefore, the conductor must have a velocity of 200 meters per second to cut through the magnetic field with a flux density of 0.6 Tesla, in order to induce an electromotive force of 9 volts.