Students heights in inches were obtained as part of a study and a frequency distribution was constructed with the first class having a lower limit of 50 inches. The class widths are 6 inches. What is the frequency of the second class in the distribution?

51 51 54 56 56 57 59 61 61 62 65 69 70 70 71 71 72 73

a. 10
b. 6
c. 4
d. 5

I'm not sure how to do this problem, could someone explain? I can give my own guess if you want but I would like to know how to do it first...

The frequency of the second class is 6.

Since the class width is 6 and the lower limit of the first class is 50, this means the first class goes from 50-55.  This would put the second class at 56-61.  There are 6 data points in this set that would go in the second class.

I can send a link telling you a more specific way to do this if you would like?

class A 50 to 56 five members

class B 57 to 63 five members
class C 64 to 70 four members
class D 70 to 76 six members

looks like A and B are tied for second at five

Thank you I understand now, I can figure the rest out on my own.

To find the frequency of the second class in the distribution, we need to first determine the intervals for each class. In this case, the first class has a lower limit of 50 inches, and the class widths are 6 inches.

To determine the intervals for each class, we add the class width to the lower limit. So, for the first class, we have 50 + 6 = 56 inches. The second class will then have a lower limit of 56 inches.

Next, we need to count the number of values that fall within the range of the second class.

Looking at the given data, we can identify the values that fall within the range of the second class (lower limit: 56 inches, upper limit: 62 inches):
56, 56, 57, 59, 61, 61, and 62

Counting these values, we find that there are 7 values that fall within the range of the second class.

Therefore, the frequency of the second class in the distribution is 7.

So, the correct answer is not among the given options.