What mass if calcium carbonate is produced from 2.53 mol of sodium carbonate?
Na2CO3+Ca(NO3)2—> CaCO3+2NaNO3
The equation tells you that you get 1 mol CaCO3 from 1 mol Na2CO3 which means you get 2.53 mols CaCO3 from 2.53 mols Na2CO3.
Then grams CaCO3 = mols CaCO3 x molar mass CaCO3 = ?
To determine the mass of calcium carbonate produced, we need to first establish the balanced chemical equation and the molar ratio between sodium carbonate (Na2CO3) and calcium carbonate (CaCO3).
From the balanced chemical equation:
2Na2CO3 + Ca(NO3)2 → CaCO3 + 2NaNO3
We can see that the molar ratio between Na2CO3 and CaCO3 is 2:1. This means that for every 2 moles of Na2CO3 reacted, 1 mole of CaCO3 is produced.
Given that we have 2.53 mol of Na2CO3, we can use the molar ratio to calculate the number of moles of CaCO3 produced:
2.53 mol Na2CO3 * (1 mol CaCO3 / 2 mol Na2CO3) = 1.265 mol CaCO3
Now that we have the number of moles of CaCO3, we can determine the mass using the molar mass of CaCO3. The molar mass of CaCO3 can be calculated by adding up the atomic masses of calcium (Ca), carbon (C), and three oxygen (O) atoms:
40.08 g/mol (Ca) + 12.01 g/mol (C) + 3 * 16.00 g/mol (O) = 100.09 g/mol
Finally, we can calculate the mass of CaCO3 produced:
Mass = Number of moles * Molar mass
Mass = 1.265 mol * 100.09 g/mol ≈ 126.54 g
Therefore, approximately 126.54 grams of calcium carbonate (CaCO3) would be produced from 2.53 moles of sodium carbonate (Na2CO3).