Can someone help with this question please,
The Chandrayaan-2 orbiter is orbiting the moon in a circular polar orbit at a height of 1.00×105 m above the surface. It has a mass of 2379 kg. What is the change of momentum in the orbiter from when it passes over the North Pole compared to when it passes over the South Pole?
same angular momentum
equal in magnitude but opposite in direction linear momentum
so 2 (2379) V
2379 V^2 / R = G * Mearth *2379 / R^2
so V^2 = G Mearth / R
where R = 10^5 + Rearth