Calculate the dispersive power of a crown glass of it's constrigence is 63.7 ?
To calculate the dispersive power of a crown glass, we need to know its refractive index for two different wavelengths of light. The refractive index of a material for a particular wavelength is denoted by its constrigence.
Given:
Constrigence (C) of crown glass = 63.7
To find the dispersive power, we need to determine the refractive index for at least two different wavelengths.
The formula for dispersive power (D) is given by:
D = (n2 - n1)/(λ2 - λ1)
where:
- n2: Refractive index for the second wavelength (unknown)
- n1: Refractive index for the first wavelength (unknown)
- λ2: Second wavelength of light
- λ1: First wavelength of light
Since we don't have the specific wavelengths, we cannot directly calculate the dispersive power. However, we can make some observations that may help.
Crown glass usually has a dispersive power in the range of 0.03 to 0.04.
If we assume a typical dispersive power of 0.035 for crown glass, we can estimate the refractive index for the first wavelength (n1) as follows:
D = (n2 - n1)/(λ2 - λ1)
0.035 = (n2 - n1)/(λ2 - λ1)
Assuming that the dispersive power (D) is constant for different wavelengths, we can substitute D = 0.035 and rearrange the equation:
0.035(λ2 - λ1) = n2 - n1
Since we don't have specific values for λ2 and λ1, we can estimate their difference (λ2 - λ1) as 1. This is a rough assumption considering the visible light spectrum.
0.035 = n2 - n1
Now, we can assume a reasonable value for the refractive index of the first wavelength (n1). Let's say n1 = 1.50.
0.035 = n2 - 1.50
Simplifying the equation:
n2 = 1.50 + 0.035
n2 ≈ 1.535
Here, we have approximated the refractive index of the second wavelength (n2) as 1.535.
Note: This is an estimation based on assumptions. For accurate calculations, specific values for the wavelengths are required, along with their corresponding refractive indices.