AP Chemistry

If a sample of 27.0 g of aluminum metal is added to 333 mL of 3.0 M HCL acid, the volume of hydrogen gas produced at standard temperature and pressure is
a. 2.8 L
b. 5.60 L
c. 11.2 L
d. 22.4 L

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  1. 6HCl + 2Al>>2AlCl3 + 3H2
    moles aluminum=27/27=1mole which means you need 3 moles HCL.
    moles HCl=.333*3=1.0 moles
    so the limiting reactant is HCL, giventhat, moles H2 generated=1/6 * 3*22.4 liters.

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