What average net force is required to accelerate a 9.5 g bullet from rest to 650 m/s over a distance of 0.85 m along the barrel of a rifle?
V^2 = Vo^2 + 2ad = 650^2.
0 + 1.7a = 650^2,
a = 248,529 m/s^2.
F = M*a = 0.0095 * 248,529 =
=
I know how to do it but I keep getting the wrong answer
thank you
Where did you get 0.0095?
.0095 came from converting g to kg
To find the average net force required to accelerate a bullet, we can use Newton's second law of motion, which states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration. The formula can be written as:
F = m * a
Where:
F is the net force
m is the mass of the bullet
a is the acceleration of the bullet
First, we need to convert the mass of the bullet from grams to kilograms:
mass = 9.5 g = 9.5 * 10^-3 kg
Next, we need to calculate the acceleration of the bullet. We can use the kinematic equation:
v^2 = u^2 + 2 * a * s
Where:
v is the final velocity (650 m/s)
u is the initial velocity (0 m/s, since the bullet starts from rest)
a is the acceleration
s is the distance covered (0.85 m)
Rearranging the equation, we can solve for acceleration:
a = (v^2 - u^2) / (2 * s)
a = (650^2 - 0^2) / (2 * 0.85)
Now, plug in the values and calculate the acceleration.
I will teach you how to do the problem with different numbers so you can do it by yourself and learn. I learned this last year.
What average force is needed to accelerate a 7.00-gram pellet from rest to 125m/s over distance of a .800m along the barrel of a rifle?
You would do a = (V^2-Vo^2)/2d.
a = (15625-0)/1.60 = 9766 m/s^2.
F = ma = 0.007 * 9766 = 68.4 N.
Hope this helps! Make sure you understand this question.