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Box A contained only 50 cent coins while Box B contained only 20 cents coins, Box B has 60 more coins than Box A but the value of all the coins in Box A is $4.50 more than the value of all the coins in Box B. Find the amount of money in Box A.

Please help me to solve this question, thanks so much.

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  1. number of coins in box B ---- b , 20 cent pieces
    number of coins in box A ---- a , 50 cent pieces

    equation dealing with number of coins:
    b = a+60

    equation dealing with value of coins:
    50a - 20b = 450
    5a - 2b = 45
    use substitution:
    5a - 2(a+60) = 45
    5a - 2a - 120 = 45
    3a = 165
    a = 55 , then b = 115

    check:
    Box A contains 55(50) = $27.50
    box B contains 20(115) = $23.00
    box A contains 27.50 - 23.00 more , or $4.50
    (my answer is correct)

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    Reiny

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