a person walks 400m north along one side of a rectangular field and then 300 m along the other side, the walk takes 10 min, calculate the av. velocity of the person?
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If the person had walked from one corner of the rectangle to the opposite corner, he would have walked
only 500m. Since he chose the longest
route, he walked a total of 700m(300+400).
d = Vt,
V = d/t = 700m / 10min = 70m/min =
70m / 60s = 1.17m/s.
To calculate the average velocity of the person, we need to determine the total displacement and the total time taken.
In this scenario, the person walks 400m north along one side of the rectangular field and then 300m along the other side. Since the two sides are perpendicular, we can consider this as a right-angled triangle.
Using the Pythagorean theorem, we can find the total displacement:
Displacement = √((400m)^2 + (300m)^2) (using a^2 + b^2 = c^2)
= √(160000m^2 + 90000m^2)
= √250000m^2
= 500m
The person takes 10 minutes to complete the walk.
Therefore, Average Velocity = Total Displacement / Total Time Taken
= 500m / 10 min
= 50 m/min
So, the average velocity of the person is 50 m/min.