In a 0.250 M solution of Na3PO4 the concentration of sodium ions would be
0.750
To find the concentration of sodium ions in a solution of Na3PO4, we need to consider the dissociation of Na3PO4. Na3PO4 dissociates into 3 sodium ions (Na+) and 1 phosphate ion (PO4^3-).
Since the concentration of the Na3PO4 solution is given as 0.250 M, this means that there are 0.250 moles of Na3PO4 in every liter of the solution.
Since Na3PO4 dissociates into 3 sodium ions, the concentration of sodium ions can be calculated by multiplying the concentration of Na3PO4 by the number of sodium ions produced per formula unit:
Concentration of sodium ions = Concentration of Na3PO4 x 3
Concentration of sodium ions = 0.250 M x 3
Concentration of sodium ions = 0.750 M
Therefore, the concentration of sodium ions in a 0.250 M solution of Na3PO4 is 0.750 M.