A toy car runs off the edge of a table that
is 1.385 m high. The car lands 0.378 m from
the base of the table.
How long does it take for the car to fall?
Answer in units of s.
What is the horizontal velocity of the car?
Answer in units of m/s.
y = Yi + 0 * t - 4.9 * t^2
0 = 1.385 - 4.9 t^2
t^2=.283
t = .532 seconds falling
.378 = u t = u (.532)
so
u = .710 m/s
To find the time it takes for the car to fall, we can use the equation for free fall:
h = (1/2) * g * t^2
where:
h is the height (1.385 m),
g is the acceleration due to gravity (approximately 9.8 m/s^2),
and t is the time we are trying to find.
Rearranging the equation, we get:
t^2 = (2 * h) / g
t = √[(2 * h) / g]
Substituting the values, we have:
t = √[(2 * 1.385) / 9.8]
t ≈ √[0.2818]
t ≈ 0.531 s
So, it takes approximately 0.531 seconds for the car to fall.
To find the horizontal velocity of the car, we need to use the equation:
v = d / t
where:
v is the velocity,
d is the horizontal distance (0.378 m),
and t is the time taken (0.531 s).
Substituting the values, we have:
v = 0.378 / 0.531
v ≈ 0.712 m/s
Therefore, the horizontal velocity of the car is approximately 0.712 m/s.