In a word game, you choose a tile from a bag, replace it, and then choose another. If there are 21 vowels and 15 consonants, what is the probability you will choose a consonant and then a vowel? Can someone assist me? Thank you!
36 total tiles, so
P(cons,vowel) = 15/36 * 21/36
Its 35/144
Absolutely! I'll be happy to help you calculate the probability for choosing a consonant and then a vowel.
To find the probability, we need to find the ratio of the number of favorable outcomes (consonant then vowel) to the total number of possible outcomes.
First, let's determine the total number of tiles in the bag. Since we have 21 vowels and 15 consonants, the total number of tiles is 21 + 15 = 36.
The probability of choosing a consonant on the first draw is the number of consonants divided by the total number of tiles:
P(consonant) = number of consonants / total number of tiles
P(consonant) = 15 / 36
After replacing the tile back in the bag, there are still 15 consonants and 36 total tiles.
Now, for the second draw, to calculate the probability of choosing a vowel, we divide the number of vowels by the total number of tiles:
P(vowel) = number of vowels / total number of tiles
P(vowel) = 21 / 36
Since these two events (consonant and then vowel) are independent, we can multiply the probabilities together to find the overall probability:
P(consonant and then vowel) = P(consonant) x P(vowel)
P(consonant and then vowel) = (15 / 36) x (21 / 36)
Calculating this expression gives us the probability of choosing a consonant and then a vowel in the word game.
My options are:
35/4, 35/8, 1/36 or 35/144.
I'm still confused...thx!