A plane cruising at 232 m/s accelerates at 14 m/s2 for 4.7 s.
What is its final velocity? Answer in units of m/s.
How far will it have traveled in that time? Answer in units of m.
a. V = Vo + 0.5*a*t^2 =
b. d = Vo*t + 0.5*a*t^2 = 232*4.7 + 0.5*14*4.7^2 =
for a what is vo??
vo is 232
To find the final velocity of the plane, you can use the following equation:
final velocity = initial velocity + (acceleration * time)
Given:
- Initial velocity (before acceleration) = 232 m/s
- Acceleration = 14 m/s^2
- Time = 4.7 s
Let's substitute these values into the equation and calculate the final velocity:
final velocity = 232 m/s + (14 m/s^2 * 4.7 s)
final velocity = 232 m/s + 65.8 m/s
final velocity = 297.8 m/s
So, the plane's final velocity is 297.8 m/s.
To calculate the distance traveled by the plane, you can use the following equation:
distance = (initial velocity * time) + (0.5 * acceleration * time^2)
Let's substitute the given values and calculate the distance:
distance = (232 m/s * 4.7 s) + (0.5 * 14 m/s^2 * (4.7 s)^2)
distance = 1089.4 m + (0.5 * 14 m/s^2 * 22.09 s^2)
distance = 1089.4 m + 154.63 m
distance = 1244.03 m
So, the plane will have traveled 1244.03 m in that time.