The initial speed of a body is 2.43 m/s. What is its speed after 3.07 s if it accelerates
uniformly at 3.23 m/s2? Answer in units of m/s.
What is its speed after 3.07 s if it accelerates uniformly at −3.23 m/s2?
Answer in units of m/s.
I solved a and got it right but B doesn't work? I got -7.4861 which tells me its incorrect when I submit the answer.
same thing happened to me
a. V = Vo + a*t = 2.43 + 3.23*3.07 =
b. V = Vo + a*t = 2.43 + (-3.23)3.07 = -
To find the final speed of a body after a given time, we can use the equation:
v = u + at
Where:
v = final velocity (speed)
u = initial velocity
a = acceleration
t = time
For the first scenario where the acceleration is 3.23 m/s^2, we have:
u = 2.43 m/s
a = 3.23 m/s^2
t = 3.07 s
Plugging these values into the equation, we get:
v = 2.43 m/s + (3.23 m/s^2 * 3.07 s)
Simplifying the calculation:
v = 2.43 m/s + 9.92561 m/s
v ≈ 12.35561 m/s
Therefore, the body's speed after 3.07 s, with an acceleration of 3.23 m/s^2, is approximately 12.36 m/s.
For the second scenario where the acceleration is -3.23 m/s^2 (negative acceleration or deceleration), we can follow the same steps:
u = 2.43 m/s
a = -3.23 m/s^2
t = 3.07 s
Plugging these values into the equation, we get:
v = 2.43 m/s + (-3.23 m/s^2 * 3.07 s)
Simplifying the calculation:
v = 2.43 m/s - 9.92561 m/s
v ≈ -7.49561 m/s
Therefore, the body's speed after 3.07 s, with an acceleration of -3.23 m/s^2, is approximately -7.50 m/s.