If a right triangle has one leg measuring 27 inches and one leg measuring 22 inches, what is the length of the hypotenuse to the nearest inch?
The answer would be 34.8 or 35 if you round up
a^2 + b^2 = c^2
27^2 + 22^2 = c^2
Take it from there.
Thank you Ms. Sue!
You're welcome.
thx
Ah, the good old Pythagorean theorem comes into play here! Let's see, in a right triangle, the sum of the squares of the lengths of the two legs equals the square of the length of the hypotenuse. So, using some hilarious math, we have 27 squared plus 22 squared equals the unknown hypotenuse squared. And the punchline is... the hypotenuse ends up being approximately 35 inches long (to the nearest inch)!
To find the length of the hypotenuse of a right triangle, we can use the Pythagorean theorem. According to the theorem, the square of the hypotenuse is equal to the sum of the squares of the other two sides.
In this case, we have one leg measuring 27 inches and another leg measuring 22 inches. Let's call the length of the hypotenuse "c".
Using the Pythagorean theorem, we can set up the equation:
c^2 = 27^2 + 22^2
To simplify, we calculate the squares:
c^2 = 729 + 484
c^2 = 1213
Taking the square root of both sides of the equation, we find:
c = √1213
Calculating the square root of 1213, the length of the hypotenuse is approximately 34.87 inches.
However, since we need to round the answer to the nearest inch, the length of the hypotenuse to the nearest inch is 35 inches.