If 0.790 mol of solid TiO2 and 8.53 g of solid C are reacted stoichiometrically according to the balanced equation, how many moles of solid TiO2 remain?
3TiO2(s) + 4C(s) + 6Cl2(g) → 3TiCl4(l) + 2CO2(g) + 2CO(g)
Change C to moles.
8.53 g/12.01 = ?? mols
Now convert moles TiO2 to moles of any one of the products, say TiCl4.
Convert moles C to moles TiCl4.
That will give you the limiting reagent; either TiO2 or C.
Using the limiting reagent (which I assume will be C), convert moles C to moles TiO2 and subtract from the initial moles of TiO2 to find the amount of TiO2 remaining after reaction.
To find the number of moles of solid TiO2 that remain, we first need to determine the number of moles of TiO2 that react.
First, we need to convert the mass of solid C into moles. We can do this by using the molar mass of carbon (C), which is 12.01 g/mol.
moles of C = mass of C / molar mass of C
moles of C = 8.53 g / 12.01 g/mol
moles of C ≈ 0.710 mol
Now we need to find the number of moles of TiO2 that reacts with the moles of C.
According to the balanced equation, the stoichiometric ratio between TiO2 and C is 3:4. This means that for every 3 moles of TiO2, 4 moles of C react.
So, using the stoichiometric ratio, we can determine the number of moles of TiO2 that react:
moles of TiO2 react = (0.710 mol C) * (3 mol TiO2 / 4 mol C)
moles of TiO2 react ≈ 0.5325 mol
Now that we know the number of moles of TiO2 that react, we can subtract this from the initial number of moles of TiO2 (0.790 mol) to find the remaining moles of TiO2.
moles of TiO2 remain = 0.790 mol - 0.5325 mol
moles of TiO2 remain ≈ 0.2575 mol
Therefore, approximately 0.2575 moles of solid TiO2 remain after the reaction.