A particle of mass 5kg initially at rest is acted upon by two mutually perpendicular forces 12N And 15N.if the particle move in the direction OA,calculate the magnitude of the acceleration?
the resultant force is ... √(12^2 + 15^2) ... in N
a = f / m
To calculate the magnitude of the acceleration, we can use Newton's second law of motion, which states that the acceleration of an object is equal to the net force acting on it divided by its mass.
In this scenario, the particle is acted upon by two mutually perpendicular forces, 12N and 15N. We need to find the net force by combining these two forces. Since the forces are perpendicular, we can use the Pythagorean theorem to find the magnitude of the net force.
Net force = sqrt((12N)^2 + (15N)^2)
= sqrt(144N^2 + 225N^2)
= sqrt(369N^2)
≈ 19.21N
Now, we can use Newton's second law of motion to find the acceleration.
Acceleration = Net force / Mass
= 19.21N / 5kg
≈ 3.84 m/s^2
Therefore, the magnitude of the acceleration is approximately 3.84 m/s^2.