Write the net ionic equation for the following molecular equation.
3FeI2 (aq) + 2(NH4)3PO4 (aq) --> Fe3(PO4)2 (s) + 6NH4I (aq)
(Use the lowest possible coefficients. Use the pull-down boxes to specify states such as (aq) or (s). If a box is not needed, leave it blank.)
I'm unclear about the boxes and I don't see any pull down boxes.
3FeI2 (aq) + 2(NH4)3PO4 (aq) --> Fe3(PO4)2 (s) + 6NH4I (aq)
3Fe^2+(aq) + 6I^-(aq) + 6NH4^+(aq) + 2PO4^3- (aq) ==> Fe3(PO4)2(s) + 6NH4^+(aq) + 6I^-(aq)
Now cancel those ions that appear on both sides to obtain the final which is the net ionic equation.
3Fe^2+(aq) + 2PO4^3-(aq) ==> Fe3(PO4)2 (s)
To write the net ionic equation, we first need to write the balanced molecular equation.
The balanced molecular equation is:
3FeI2 (aq) + 2(NH4)3PO4 (aq) → Fe3(PO4)2 (s) + 6NH4I (aq)
Now, let's write the ionic equation by separating all the soluble ionic compounds into their respective ions:
3Fe^2+ (aq) + 6I^- (aq) + 6NH4^+ (aq) + 2PO4^3- (aq) → Fe3(PO4)2 (s) + 6NH4^+ (aq) + 6I^- (aq)
Next, simplify the equation by removing the spectator ions that do not participate in the reaction. In this case, NH4^+ and I^- are spectator ions because they appear on both sides of the equation:
3Fe^2+ (aq) + 2PO4^3- (aq) → Fe3(PO4)2 (aq)
Therefore, the net ionic equation is:
3Fe^2+ (aq) + 2PO4^3- (aq) → Fe3(PO4)2 (aq)
Note: The state of Fe3(PO4)2 is assumed to be aqueous (aq) because the prompt did not specify its state.
To write the net ionic equation, we need to first write the balanced molecular equation.
The given equation is:
3FeI2 (aq) + 2(NH4)3PO4 (aq) --> Fe3(PO4)2 (s) + 6NH4I (aq)
Now, let's break down the chemical compounds into their respective ions. Ions that are aqueous (aq) will dissociate into their constituent ions, while those that are solid (s) will remain together as compounds.
Breaking down the compounds:
3FeI2 (aq) --> 6Fe2+ (aq) + 6I- (aq)
2(NH4)3PO4 (aq) --> 6NH4+ (aq) + 2PO43- (aq)
Fe3(PO4)2 (s) remains intact since it is a solid (s)
6NH4I (aq) --> 6NH4+ (aq) + 6I- (aq)
Now, we can write the net ionic equation by canceling out any spectator ions that appear on both sides of the equation. In this case, the ions Fe2+ and I- appear on both sides and can be canceled out.
Net ionic equation:
6Fe2+ (aq) + 2PO43- (aq) --> Fe3(PO4)2 (s)
Thus, the net ionic equation for the reaction is:
6Fe2+ (aq) + 2PO43- (aq) --> Fe3(PO4)2 (s)