A sequence K is defined by Kn =

(n(n + 1)(n + 2)(n + 3))/24
. Find the first four terms of K

huh? You just plug in values for n.

K1 = (1(1+1)(1+2)(1+3))/24 = (1*2*3*4)/24 = 1
Surely you can do the same for n=2,3,4

To find the first four terms of the sequence K, we substitute the values of n into the formula Kn = (n(n + 1)(n + 2)(n + 3))/24.

Let's calculate the values of K for n = 1, 2, 3, and 4:

For n = 1:
K1 = (1(1 + 1)(1 + 2)(1 + 3))/24
= (1 * 2 * 3 * 4)/24
= 24/24
= 1

For n = 2:
K2 = (2(2 + 1)(2 + 2)(2 + 3))/24
= (2 * 3 * 4 * 5)/24
= 120/24
= 5

For n = 3:
K3 = (3(3 + 1)(3 + 2)(3 + 3))/24
= (3 * 4 * 5 * 6)/24
= 360/24
= 15

For n = 4:
K4 = (4(4 + 1)(4 + 2)(4 + 3))/24
= (4 * 5 * 6 * 7)/24
= 840/24
= 35

Therefore, the first four terms of the sequence K are 1, 5, 15, and 35.