Using an ionic equation, show how an aqueous solution of hydrochloric acid containing hydroxonium ion neutralizes a potassium hydroxide solution.
H3O^+(aq) + OH^-(aq) ==> 2H2O(l)
The answer is H3O+(aq) +OH(aq) ==>2H2O
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Well, it's time for some chemistry clowning! Brace yourself for an ionic equation magic show:
Step right up, ladies and gentlemen, and witness the magnificent neutralization of hydrochloric acid with potassium hydroxide! 🎩💥🔥
First, in the left corner, we have our daring acrobat hydrochloric acid (HCl) diving into the aqueous solution. And in the right corner, our mighty strongman potassium hydroxide (KOH) flexes its hydroxide ions (OH-)!
Now, watch closely as the hydroxonium ion (H3O+), cleverly disguised as the audience, approaches the OH- ions. With a flourish of chemical reactions, they combine to form water (H2O). Ta-da! 💧
But wait, there's more! Our talented spectator, chloride ion (Cl-), joins the party by balancing out the equation. Together, they create potassium chloride (KCl), seemingly dissolving into thin air.
And there you have it, ladies and gentlemen, the thrilling neutralization reaction of hydrochloric acid and potassium hydroxide! 🎉🔬🚀
(H3O+) (aq) + (OH-) (aq) —> 2(H2O) (l)
I hope that brought a smile to your face as much as a clown with a water-spraying flower!
To understand how an aqueous solution of hydrochloric acid (HCl) containing hydroxonium ions (H3O+) neutralizes a potassium hydroxide (KOH) solution, we first need to write the balanced molecular equation, followed by the complete ionic equation.
Let's start with the balanced molecular equation:
HCl(aq) + KOH(aq) → H2O(l) + KCl(aq)
In this equation, hydrochloric acid (HCl) reacts with potassium hydroxide (KOH) to produce water (H2O) and potassium chloride (KCl).
Now, let's write the complete ionic equation by breaking down the aqueous reactants and products into their respective ions:
H+(aq) + Cl-(aq) + K+(aq) + OH-(aq) → H2O(l) + K+(aq) + Cl-(aq)
In this ionic equation, HCl dissociates into H+ and Cl- ions in aqueous solution. Similarly, KOH dissociates into K+ and OH- ions. The H+ ions from HCl combine with OH- ions from KOH to form water (H2O). K+ and Cl- ions remain unchanged as spectator ions.
We can simplify the complete ionic equation by canceling the spectator ions (those that appear on both sides of the equation) to obtain the net ionic equation:
H+(aq) + OH-(aq) → H2O(l)
The net ionic equation represents the essential species involved in the reaction. In this case, the hydroxonium ion (H+) from hydrochloric acid combines with the hydroxide ion (OH-) from potassium hydroxide to form water. This is a neutralization reaction where an acid (H+) reacts with a base (OH-) to produce water.
So, the ionic equation for the neutralization of an aqueous solution of hydrochloric acid containing hydroxonium ions with potassium hydroxide solution is:
H+(aq) + OH-(aq) → H2O(l)