A given wire of resistance 10ohm has a length of 5m and a cross sectional area of 4.0*10^-3m^2,calculate the conductivity of the wire .
please help me out I don't understand it
you know that conductivity is measured in 1/Ω-m
Recall that conductivity σ = L/RA
You have the numbers, so plug them in.
To calculate the conductivity of the wire, you need to know the formula for conductivity and the given values of resistance, length, and cross-sectional area of the wire.
The formula for conductivity (σ) is:
σ = 1/ρ
Where:
ρ is the resistivity of the material
σ is the conductivity
The resistivity (ρ) can be calculated using the resistance (R), length (L), and cross-sectional area (A) using the formula:
ρ = (R * A) / L
Now let's substitute the given values into the formula to find the resistivity:
R = 10 ohm
L = 5 m
A = 4.0 * 10^-3 m^2
First, calculate the resistivity:
ρ = (10 ohm * 4.0 * 10^-3 m^2) / 5 m
Multiply 10 ohm by 4.0 * 10^-3 m^2:
ρ = (0.04 ohm * m^2) / 5 m
Divide 0.04 ohm * m^2 by 5 m:
ρ = 0.008 ohm * m
Now that we have the resistivity, we can calculate the conductivity:
σ = 1 / ρ
Divide 1 by 0.008 ohm * m:
σ = 1 / 0.008 ohm * m
σ = 125 S/m
So, the conductivity of the wire is 125 S/m.