Find the measures of angles in triangle ABC if m∠A: m∠B: m∠C= 2:3:4
can you help me with this 2/3 times 4/5
2/3 x 4/5 is 8/15
Find the measures of angle ABC if m<a:m<b:m<c=2:3:4
can i ask bobo ba kayo
Bro, the ones who say a=40 b=60 and c=80 are right, u rsm cheater need to put the degrees sign at the end
To find the measures of angles in triangle ABC, we need to determine the ratio of the measures of the angles.
Given that the ratio of the measures of angles A, B, and C is 2:3:4, we can assume that the measures of the angles are 2x, 3x, and 4x, respectively.
To find the value of x, we need to consider that the sum of the measures of the interior angles in any triangle is 180 degrees.
Therefore, we can set up the equation:
2x + 3x + 4x = 180
Simplifying the equation, we have:
9x = 180
Dividing both sides of the equation by 9, we find:
x = 20
Now that we know the value of x, we can find the measures of angles A, B, and C:
Angle A = 2x = 2 * 20 = 40 degrees
Angle B = 3x = 3 * 20 = 60 degrees
Angle C = 4x = 4 * 20 = 80 degrees
Therefore, the measures of angles A, B, and C in triangle ABC are 40 degrees, 60 degrees, and 80 degrees, respectively.
m∠A = 40 degrees
m∠B = 60 degrees
m∠C = 80 degrees
180/4 =60
60-180=120
120/3=40
40+60=100
180-100
A=40
B=60
C=80
Let the angles have measures 2x,3x,4x
Then 2x+3x+4x = 180
and the rest is easy.