10.0g of caco3 was dissolved in water and made up to 1.0dm3. if 25.00cm3 of this solution requires 24.90 of 0.100mol/dm3 HCL for neutralization, calculate the molar mass of the acid salt and the atomic mass of X
To calculate the molar mass of the acid salt (CaCO3) and the atomic mass of X, we can use the concept of stoichiometry and the given information about the neutralization reaction.
First, let's set up the balanced chemical equation for the neutralization reaction between CaCO3 and HCl:
CaCO3 + 2HCl → CaCl2 + CO2 + H2O
From the equation, we know that one mole of CaCO3 reacts with 2 moles of HCl. Therefore, the number of moles of HCl required to neutralize 25.00 cm3 (or 0.0250 dm3) of the CaCO3 solution can be calculated using the following equation:
moles of HCl = concentration of HCl × volume of HCl
moles of HCl = 0.100 mol/dm3 × 0.02490 dm3
moles of HCl = 0.00249 mol
Since the reaction is 1:2 between CaCO3 and HCl, the number of moles of CaCO3 present in the 25.00 cm3 of solution is half the number of moles of HCl:
moles of CaCO3 = 0.00249 mol / 2
moles of CaCO3 = 0.00125 mol
Now, we can calculate the number of moles of CaCO3 in 1.0 dm3 (or 1000 cm3):
moles of CaCO3 (in 1.0 dm3) = moles of CaCO3 (in 25.00 cm3) × (1000 cm3 / 25.00 cm3)
moles of CaCO3 (in 1.0 dm3) = 0.00125 mol × 40
The molar mass of CaCO3 can be calculated by dividing the mass of CaCO3 by the number of moles:
molar mass of CaCO3 = mass of CaCO3 / moles of CaCO3
mass of CaCO3 = 10.0 g (given)
moles of CaCO3 = 0.00125 mol (from the calculation above)
molar mass of CaCO3 = 10.0 g / 0.00125 mol
Therefore, the molar mass of CaCO3 is 8000 g/mol.
Next, we need to calculate the atomic mass of X. Since the formula for calcium carbonate (CaCO3) consists of one calcium (Ca) atom, one carbon (C) atom, and three oxygen (O) atoms, we need to find the atomic mass of X.
molar mass of CaCO3 = (atomic mass of Ca) + (atomic mass of C) + (3 × atomic mass of O) + (atomic mass of X)
8000 g/mol = (40 g/mol) + (12 g/mol) + (3 × 16 g/mol) + (atomic mass of X)
To solve for the atomic mass of X, we rearrange the equation:
atomic mass of X = 8000 g/mol - (40 g/mol + 12 g/mol + 3 × 16 g/mol)
Therefore, the atomic mass of X is 56 g/mol.
In summary, the molar mass of the acid salt (CaCO3) is 8000 g/mol, and the atomic mass of X is 56 g/mol.