Joe is six years older than Mary ,while Mary is 4 years older than Jane .the sum of their ages is 53.how old is Jane?
First, create an equation with the information you have.
J is Joe
M is Mary
A is Jane
J + M + A = 53
Next step --> convert them to 1 single unit, A
Mary is 4 years older than Jane so she is A + 4
Joe is 6 years older than Mary who is 4 years older than Jane so he is A+10
Next put it back in the equation
A+10+A+4+A=53
10+4 is fourteen so subtract 14 from both sides. (53-14=39)
3A=39
Divide both sides by 3
A=13
Jane is 13 years old
(Mary is 19 and Joe is 23)
I hope this helps!
Joe = Mary + 6
Mary = Jane + 4
so, what else do you know?
...
To find out Jane's age, let's follow a step-by-step approach:
1. Assign variables:
Let's assign variables to represent the ages of Jane, Mary, and Joe.
Jane's age = x
Mary's age = x + 4 (Jane is 4 years younger than Mary)
Joe's age = x + 4 + 6 = x + 10 (Joe is 6 years older than Mary)
2. Set up the equation:
The sum of their ages is given as 53, so we can write the equation:
x + (x + 4) + (x + 10) = 53
3. Solve the equation:
Simplify the equation by combining like terms:
3x + 14 = 53
Subtract 14 from both sides of the equation:
3x + 14 - 14 = 53 - 14
3x = 39
Divide both sides of the equation by 3:
3x/3 = 39/3
x = 13
4. Find Jane's age:
Substitute the value of x back into the equation:
Jane's age = x = 13
Therefore, Jane is 13 years old.