8{[5(y-5)+18}-{2(5y-3)+1]}=

simplify your answer
someone help me

First, distribute.

5 times y is 5y and 5 times -5 is -25. So the first part of the equation is:

8(5y-25 + 18)

Then distribue on the other side. Then solve from there by subtracting the numbers that do not have variables and dividing the ones that do have variables next to them.

If you need any more help, or you want me to be more specific, just post another new comment/response. Hope I helped!