An iron weight is 200lb in air how much force is required when it is emerged in water to support an anchor

Iron= 480 lb/ft cube
Sea water=64lb/ft cube?

what is the answer

density= mass/volume or volume=mass/density

for iron, volume= 200lb/480lb/ft^3=.417 ft^3
weight submerged=200lb - weight of .417ft^3 seawater
and weight of seawater= 64*.417 lb

To calculate the force required to support the anchor in water, we first need to determine the volume of the iron weight and the volume of water that will displace the weight when it is immersed.

1. Find the volume of the iron weight:
Given that the iron weight has a density of 480 lb/ft³, and its mass is 200 lb, we can use the formula:
Volume = Mass / Density
Volume = 200 lb / 480 lb/ft³ = 0.4167 ft³

2. Calculate the volume of water displaced:
When the weight is immersed in water, it displaces a volume of water equal to its own volume. So, the volume of water displaced is also 0.4167 ft³.

3. Calculate the buoyant force:
Since the weight is immersed in water, it experiences an upward buoyant force equal to the weight of the water displaced. The density of seawater is given as 64 lb/ft³.

Buoyant Force = Density of Water × Volume of Water Displaced
Buoyant Force = 64 lb/ft³ × 0.4167 ft³ = 26.67 lb

Therefore, the force required to support the iron weight in the water (to counteract its weight) is 26.67 lb.