Consider the following right triangle with right angle, P, where PQ=4 units and PR=5 units.
Right triangle PQR with right angle P. The sides are labeled as follows: PQ=4 and PR=5.
Step 1 of 5
What is the length of the hypotenuse of △PQR?
Round your answer to the nearest tenth.
QR≈
help please i got 6 and it says close but i cant figure it out.
you will have to use Pythagoras
hyp^2 = 4^2 + 5^2 = 41
hyp = √41 = 6.403... , round this to the nearest tenth.
To find the length of the hypotenuse QR in a right triangle, you can use the Pythagorean theorem, which states that in a right triangle, the sum of the squares of the lengths of the two shorter sides is equal to the square of the length of the hypotenuse.
In this case, we have PR as one of the shorter sides with a length of 5 units, and PQ as the other shorter side with a length of 4 units.
So, using the Pythagorean theorem:
PR² + PQ² = QR²
Substituting the given values:
5² + 4² = QR²
25 + 16 = QR²
41 = QR²
To find the length of QR, we need to take the square root of both sides of the equation:
√41 ≈ 6.4
Rounding to the nearest tenth, the length of QR is approximately 6.4 units.
Therefore, the correct answer is 6.4.