Aluminum has specific heat capacity of 900J/kg what does this mean
PER DEGREE !!
In those units degree Centigrade or Kelvin (same difference K =C +273)
It means that if you put 900 Joules of heat into one kilogram of Al its temperature will go up one degree.
heat in = specific heat * mass in kilograms * increase in temperature
It means it takes 900J to raise 1 kg one decree C.
Thank you :- Now I have just over 4 lb of steam coal = 70,000,000 j of heat energy. Now can you tel me if I heat just over 4lb of 2 mm O.D. hard aluminium wire at say 1,000 Degrees C how much heat will get in "J" [The heat must exclude the electrical plasma input to combust the Aluminium]
best wishes :-)
specific heart of aluminium is 900j/kgco. how much the heart capacity of 2gram aluminium
The specific heat capacity of a material refers to the amount of heat energy required to raise the temperature of one kilogram (kg) of that material by one degree Celsius (°C) or one Kelvin (K). In the case of aluminum, its specific heat capacity is 900 J/kg°C.
To better understand what this means, let's break it down:
1. "Specific heat capacity": This term refers to the heat energy required to raise the temperature of a specific amount of a substance by a specific amount. It is often denoted by the symbol "c" and is measured in units of joules per kilogram per degree Celsius or joules per kilogram per Kelvin (J/kg°C or J/kgK).
2. "900 J/kg°C": This value specifically tells us that it takes 900 joules of heat energy to raise the temperature of one kilogram of aluminum by one degree Celsius.
Therefore, if you have a given mass of aluminum (in kilograms) and you want to calculate the heat energy required to raise its temperature by a certain amount, you can use the specific heat capacity. The formula for calculating heat energy (Q) is:
Q = m * c * ΔT
Where:
- Q represents the heat energy (in joules),
- m is the mass of the substance (in kilograms),
- c is the specific heat capacity (in J/kg°C),
- ΔT represents the change in temperature (in °C or K).
By plugging in the values you know into this equation, you can find the amount of heat energy required or calculate other variables if needed.