Five times a certain number exceeds 19 by 6.
How do I solve this in algebraic form?
x = your number
5 x = 19 + 6
5 x = 25
x = 25 / 5
x = 5
To solve this equation algebraically, let's break it down step by step:
1. Let's represent the unknown number with a variable, say "x."
2. The phrase "Five times a certain number" can be written as "5x" or "5 times x."
3. The phrase "exceeds 19 by 6" can be written as "19 + 6" or "19 added to 6," which is equal to 25.
4. Combining the two parts of the equation, "Five times a certain number exceeds 19 by 6" can be expressed as the equation: 5x = 25.
5. To isolate the variable "x" on one side of the equation, we need to divide both sides of the equation by 5. This results in: x = 5.
Therefore, the solution to the equation is x = 5.
To solve this problem in algebraic form, let's break it down step by step.
Step 1: Translate the given problem into an equation.
We are told that "Five times a certain number exceeds 19 by 6." Let's assume the unknown number is represented by the variable "x." So, five times this number can be written as 5x. According to the problem, this expression exceeds 19 by 6, which can be represented as 19 + 6. Combining these expressions, we get the equation:
5x = 19 + 6
Step 2: Simplify the equation.
On the right side of the equation, we can combine 19 and 6 to get 25. So now the equation becomes:
5x = 25
Step 3: Solve for x.
To solve for x, we need to isolate it on one side of the equation. In this case, we can divide both sides of the equation by 5:
5x/5 = 25/5
This simplifies to:
x = 5
Step 4: Interpret the solution.
The solution to the equation is x = 5, which means that the certain number we were looking for is 5.