A coil of 50turns is pulled in 0.02secs from between the poles of a magnet where it's area includes 31× 10^-5 Weber to a place where it's area includes 1 x 10^-5 Weber.Determine the average emf induced in the coil
A.0.75V
B.0.075
C.75V
D.7.5V?
To determine the average emf induced in the coil, we can use Faraday's law of electromagnetic induction, which states that the emf induced in a loop is equal to the negative rate of change of magnetic flux through the loop.
The formula to calculate the average emf is:
Emf = ΔΦ / Δt
Where:
Emf = Electromotive force (average emf induced in the coil)
ΔΦ = Change in magnetic flux through the coil
Δt = Change in time
In this case, we are given the change in magnetic flux and the change in time. Let's substitute the values:
ΔΦ = (final magnetic flux - initial magnetic flux) = (1 × 10^-5 Weber - 31 × 10^-5 Weber) = -30 × 10^-5 Weber (negative sign indicates the direction of the change)
Δt = 0.02 seconds
Now we can plug in these values into the formula:
Emf = (-30 × 10^-5 Weber) / (0.02 seconds)
Simplifying the equation:
Emf = -1.5 V
Since the negative sign of the emf indicates the direction of the induced current, we take the absolute value:
Emf = 1.5 V
Therefore, the average emf induced in the coil is 1.5 V.
So, the correct answer is not provided in the options given. None of the options A, B, C, or D are correct.