A sound pulse sent vertically downward into the earth is reflected from two different ways of the earth such that echoes are heard after 1.25s and 1.45s, assuming the speed of the pulse is 200ms-1 calculate the distance between the lattes?
pulse 1 goes outbound for 1.25/2 = .650 seconds
pulse 2 goes outbound for 1.45/2 = .725 seconds
difference in one way time = .725 - .650 = .075 seconds
so
difference in range = 200 m/s * .075 s = 15 meters
the 2nd echo is 200 ms behind the 1st
... 100 ms out and 100 ms back
200 m/s * 100 ms = ? m
Using: V= 2x/t..
x1= 200* 1.25/2 = 125 m
x2= 200* 1.45/2= 145 m.
Distance between the layers = x2 - x1 = (145 - 125) m
= 20 metres.
To calculate the distance between the two layers, we can use the formula:
Distance = (Speed of Sound × Time) / 2
Given:
Speed of sound = 200 m/s
First echo time = 1.25 s
Second echo time = 1.45 s
Let's calculate the distance between the layers:
First Echo:
Distance1 = (200 m/s × 1.25 s) / 2
Distance1 = 250 m
Second Echo:
Distance2 = (200 m/s × 1.45 s) / 2
Distance2 = 290 m
To calculate the distance between the layers, we need to find the difference between the two distances:
Distance between the layers = |Distance1 - Distance2|
Distance between the layers = |250 m - 290 m|
Distance between the layers = 40 m
Therefore, the distance between the two layers is 40 meters.