For the following function, find the values of the constants π‘Ž and 𝑏 for which the function is continuous, but not differentiable.

𝑓(π‘₯)={π‘Žπ‘₯+𝑏,π‘₯>0 & sinπ‘₯,π‘₯≀0.

as with the previous problem, you want

f(0) to match up,
but f'(0) has a break.

how about a=0, b=0
or any linear function f(x) = kx where k≠1
since f'(sinx) = 1 at x=0

To find the values of the constants π‘Ž and 𝑏 for which the function 𝑓(π‘₯) is continuous but not differentiable, we need to consider the conditions for continuity and differentiability separately.

For a function to be continuous, it needs to be defined at a point and must not have any gaps, jumps, or holes. In this case, 𝑓(π‘₯) is defined differently for π‘₯ > 0 and π‘₯ ≀ 0.

- For π‘₯ > 0, 𝑓(π‘₯) = π‘Žπ‘₯ + 𝑏. To ensure continuity, we need the left-hand limit to be equal to the right-hand limit when π‘₯ approaches 0 from the left. This means we need to evaluate π‘Žπ‘₯ + 𝑏 as π‘₯ approaches 0 from the left. Setting π‘₯ = 0 in the expression π‘Žπ‘₯ + 𝑏 gives us 𝑏. Therefore, 𝑏 needs to be equal to the value of the function at π‘₯ = 0, which is 𝑓(0) = sin(0) = 0. Hence, 𝑏 = 0.

- For π‘₯ ≀ 0, 𝑓(π‘₯) = sinπ‘₯. Since sinπ‘₯ is a well-defined function for all values of π‘₯, we don't need to consider any conditions for π‘Ž or 𝑏.

Therefore, the values of π‘Ž and 𝑏 for which the function 𝑓(π‘₯) = π‘Žπ‘₯ + 𝑏 is continuous are π‘Ž = any value and 𝑏 = 0.

Now let's discuss the differentiability of 𝑓(π‘₯). For a function to be differentiable at a point, it needs to have a well-defined derivative at that point, which means that the derivative from the left-hand side should be equal to the derivative from the right-hand side.

Looking at 𝑓(π‘₯), we observe that the derivative of 𝑓(π‘₯) = π‘Žπ‘₯ + 𝑏 with respect to π‘₯ is π‘Ž. This derivative is a constant and does not depend on π‘₯. On the other hand, when π‘₯ ≀ 0, the derivative of 𝑓(π‘₯) = sinπ‘₯ with respect to π‘₯ is cosπ‘₯, which is defined for all π‘₯.

Since the derivative of 𝑓(π‘₯) = π‘Žπ‘₯ + 𝑏 is a constant (π‘Ž) and the derivative of 𝑓(π‘₯) = sinπ‘₯ is defined for all values of π‘₯, the function 𝑓(π‘₯) is differentiable for any values of π‘Ž and 𝑏.

Therefore, the values of π‘Ž and 𝑏 for which the function 𝑓(π‘₯) is continuous but not differentiable are π‘Ž = any value and 𝑏 = 0.