A woman spent 1/3 of her money at the market,1/4 at the chemist's,1/6 at the electrical shop and had #555 left. How much money did she have to start with?
1/3+1/4+1/6
4/12+3/12+2/12=9/12
12-9/12=3/12
#555÷3/12
#555×12/3
185×12=#2220
(1/3+1/4+1/6)(x)=x-555
9/12(x)=x-555
9x/12=x-555
9x=12(x)- 12(555)
9x=12x-6660
9x-12x=-6660
-3x=-6660
x=-6660/-3
X=2220
1/3 + 1/4 + 1/6
*Find the LCM which is 12
4/12 + 3/12 + 2/12
12 - 9/12= 3/12
₦555 ÷ 3/12
185 × 12
= ₦2220
1/3x+1/9x+1/6x+555=x
9x/12+555=x
555=x-9x/12
555=x/4
cross multiply
x=#2220
1/3+1/4+1/6
find the l.c.m
4/12 +3/12+2/12=9/12
12-9/12=3/12
#555*12/3=#6660*3
=#2220
started with x
x - (1/3) x - (1/4) x - (1/6) x = 555
(12/12 - 4/12 - 3/12 -2/12)x = 555
(3/12)x = 555
(1/4 )x = 555
x = 4 * 555
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To solve this problem, we can use algebra. Let's assume that the woman had x amount of money to start with.
According to the problem, she spent 1/3 of her money at the market, which means she had (2/3)x left.
Then she spent 1/4 of this remaining money at the chemist's, which means she had (3/4)(2/3)x = (6/12)x left.
Finally, she spent 1/6 of this remaining money at the electrical shop, which means she had (5/6)(6/12)x = (30/72)x left.
We are given that she had $555 left, so we can set up the equation:
(30/72)x = 555
To solve for x, we can multiply both sides of the equation by 72/30:
x = 555 * (72/30)
Simplifying this expression gives:
x = 1330
Therefore, the woman had $1330 to start with.