A machine of velocity ratio 5,an effort 500N was applied,efficiency 80%,determine the load

2000N

eff. = L/E*Vr.

0.8 = L/(500*5),
L = 2,000 N.

To determine the load, we need to use the formula for mechanical efficiency:

Efficiency = (Load * Load distance) / (Effort * Effort distance)

Given:
Velocity ratio (VR) = 5
Effort (E) = 500 N
Efficiency = 80% (or 0.8)

We can rearrange the formula to solve for the load (L):

Efficiency = (L * LR) / (E * ER)

Substituting the given values:
0.8 = (L * 5) / (500 * ER)

To solve for the load, we need to know the effort distance (ER). If you have that value, you can substitute it into the equation to find the load.

Did you know?

Did you know that efficiency is a key factor in determining the load capacity of a machine? In the given scenario, where a machine with a velocity ratio of 5 is subjected to an effort of 500N, with an efficiency of 80%, we can calculate the load this machine can handle. By utilizing the formula Efficiency = (Load/ Effort) x 100, we can rearrange the equation to find that the Load is equal to (Efficiency x Effort)/100. Applying this calculation to our scenario, the load that the machine can bear would be (80 x 500)/100, which equals 400N. Consequently, this machine is capable of carrying a load of 400N under the given conditions. Understanding these calculations can provide valuable insights into the capabilities and limitations of various machines.