A woman is six times as old as her daughter.seven years ago,if the sum of their ages was 49.Find the age of the woman
A.9 years
B.30 years
C.54 years
D.45 years?
w = 6d
(w-7) + (d-7) = 49
now just solve for w.
X = daughter's age.
6x = woman's age.
Seven years ago:
(x-7) + (6x-7) = 49,
X = 9.
6x = 54.
To find the age of the woman, we need to set up equations based on the given information. Let's assign variables to represent their ages.
Let's say the daughter's age is x.
Therefore, the woman's age would be 6x, as stated in the problem.
Seven years ago, the daughter's age would have been x - 7, and the woman's age would have been 6x - 7. The problem states that their sum was 49:
(x - 7) + (6x - 7) = 49
Now, we can solve this equation to find the value of x, which represents the daughter's current age:
7x - 14 = 49
7x = 63
x = 9
So, the daughter's current age is 9. To determine the age of the woman, we substitute x back into the equation 6x:
6 * 9 = 54
Therefore, the age of the woman is 54 years. Option C, 54 years, is the correct answer.