Two numbers are chosen at random from three numbers 1,3,5.Find the probability that the sum of the two is not odd?
the sum of any two odd numbers is even...
1+3 = 4
1+5 = 6
3+5 = 8
100%
To find the probability that the sum of the two chosen numbers is not odd, we need to first list all the possible combinations of two numbers:
1st number: 1
2nd number: 1, 3, 5
1st number: 3
2nd number: 1, 3, 5
1st number: 5
2nd number: 1, 3, 5
Now, let's check which combinations have a sum that is not odd:
1 + 1 = 2 (even)
1 + 3 = 4 (even)
1 + 5 = 6 (even)
3 + 1 = 4 (even)
3 + 3 = 6 (even)
3 + 5 = 8 (even)
5 + 1 = 6 (even)
5 + 3 = 8 (even)
5 + 5 = 10 (even)
Out of the nine possible combinations, there are nine that have a sum that is not odd.
So the probability that the sum of the two chosen numbers is not odd is 9/9, which simplifies to 1.
Therefore, the probability is 1.