Physics

What is the magnitude of the resultant velocity for a bird flying first at a speed of 10m/s North East and then flying to south at a speed of 8m/s?

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  1. Draw the vectors. All you need here is the 3rd side of the triangle.
    Use the law of cosines.
    x^2 = 10^2 + 8^2 - 2*10*8*cos45°

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  2. Va=10cos45 E + 10 sin45 N
    Vb=-8N

    VresultN=Va+Vb=10*.707-8 N=7.07-8 N= .93S
    Vreslt= Vn + 10*.707E
    magnitude= sqrt(.93^2 + 7.07^2)

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    bobpursley
  3. All angles are measured CW from +y-axis.
    Vr = 10m/s[45o] + 8m/s[180o].

    X = 10*sin45 + 8*sin180 = 7.07 m/s.
    Y = 10*Cos45 + 8*Cos180 = -0.93 m/s.

    Vr = sqrt(X^2+Y^2).

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  4. 7.13

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  5. answer

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