Calculate the mass of displaced water when a piece of 30 cm thick iceberg with surface area 1000cm^2 floats on water
Given(density of ice=0.9g/cm^3 &density of water=1gm/cm^3
Vi = As * h = 1000 * 30 = 30,000 cm^3 = Vol. of the ice.
Vb = (Di/Dw) * Vi = (0.9/1.0) * 30,000 = 27,000 cm^3 = Vol. below surface - Vol. of water displaced.
27,000cm^3 * 1g/cm^3 = 27,000 grams = 27 kg = Mass of water displaced.
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Why did the iceberg become friends with the water? Because they both thought they were cool!
Alright, let's calculate the mass of the displaced water.
The volume of the iceberg can be calculated by multiplying its thickness (30 cm) with its surface area (1000 cm^2):
Volume of iceberg = 30 cm * 1000 cm^2 = 30,000 cm^3
Since the density of ice is given as 0.9 g/cm^3, we can now calculate the mass of the iceberg:
Mass of iceberg = 0.9 g/cm^3 * 30,000 cm^3 = 27,000 g
Now, since the iceberg is floating on water, it displaces an equal volume of water. Assuming the density of water is 1 g/cm^3, the mass of the displaced water will be equal to the mass of the iceberg.
Therefore, the mass of the displaced water is 27,000 g or 27 kg.
To calculate the mass of displaced water when an iceberg floats on water, we need to find the volume of the submerged portion of the iceberg.
Step 1: Calculate the volume of the submerged portion:
Volume = Surface Area x Thickness
Given that the surface area of the iceberg is 1000 cm² and the thickness is 30 cm:
Volume = 1000 cm² x 30 cm
Volume = 30000 cm³
Step 2: Convert the volume from cm³ to liters:
1 liter = 1000 cm³
Volume in liters = 30000 cm³ ÷ 1000
Volume in liters = 30 liters
Step 3: Calculate the mass of the displaced water:
The density of water is 1 g/cm³, which means that 1 liter of water has a mass of 1 kg.
Mass of displaced water = Volume in liters x Density of water
Mass of displaced water = 30 liters x 1 kg/liter
Mass of displaced water = 30 kg
Therefore, the mass of the displaced water when the iceberg floats on water is 30 kg.
To calculate the mass of displaced water when the iceberg floats on water, you need to use Archimedes' principle, which states that an object submerged or floating in a fluid experiences an upward buoyant force equal to the weight of the fluid it displaces.
The first step is to calculate the volume of the iceberg using its dimensions. The volume can be calculated by multiplying the surface area of the iceberg by its thickness.
Surface Area = 1000 cm^2
Thickness = 30 cm
Volume = Surface Area × Thickness
Volume = 1000 cm^2 × 30 cm
Volume = 30000 cm^3
Since the density of ice is given as 0.9 g/cm^3, we can use it to calculate the mass of the iceberg.
Mass of Iceberg = Density × Volume
Mass of Iceberg = 0.9 g/cm^3 × 30000 cm^3
Mass of Iceberg = 27000 g
Now, in order to calculate the mass of displaced water, we can use the fact that the density of water is 1 g/cm^3. The mass of the displaced water is equal to the mass of the iceberg.
Mass of Displaced Water = Mass of Iceberg = 27000 g
Therefore, the mass of displaced water when the iceberg floats on water is 27000 grams (or 27 kilograms).