factorise the following
m^2 - n^2 - mq - nq?
m^2-n^2 = (m+n)(m-n)
-mq - nq = -q(m-n)
so, what do you think?
oops
-mq-nq = -q(m+n)
To factorize the given expression, m^2 - n^2 - mq - nq, we can notice that it resembles a quadratic expression with respect to 'm' and 'q'. Let's rearrange it to make it clearer:
m^2 - mq - n^2 - nq
Now, let's group the terms:
(m^2 - mq) - (n^2 + nq)
We can now factor out the common terms from each group:
m(m - q) - n(n + q)
Finally, we can rearrange the terms to get the factored form:
(m - q)(m + n)(n + q)
So, the given expression m^2 - n^2 - mq - nq factorizes to (m - q)(m + n)(n + q).